0=-2x^2+12x+10

Solution for 0=-2x^2+12x+10 equation:

0=-2x^2+12x+10

We move all terms to the left:

0-(-2x^2+12x+10)=0

We add all the numbers together, and all the variables

-(-2x^2+12x+10)=0

We get rid of parentheses

2x^2-12x-10=0

a = 2; b = -12; c = -10;
Δ = b2-4ac
Δ = -122-4·2·(-10)
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{14}}{2*2}=\frac{12-4\sqrt{14}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{14}}{2*2}=\frac{12+4\sqrt{14}}{4}
$